I think I speak for most people when I say that I’m a good representative of the general population.

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Joined 5 years ago
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Cake day: June 29th, 2020

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  • Christian@lemmy.mltoAsklemmy@lemmy.mlWomen in Metal
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    4 days ago

    Sandra Nasić of the Guano Apes for her appearance on Apocalyptica’s Path Vol. 2.

    This song came to mind for me too. Cult is Apocalyptica’s best album, but that song basically ruined my ability to enjoy it as it was made because putting it on straight-up I’m immediately disappointed by the lack of vocals in track 1.

    There was another track from that album that they reworked to add a guest vocalist to, I think track 8, but that one didn’t hit me as an improvement over the original.


  • Christian@lemmy.mltoAsklemmy@lemmy.mlWomen in Metal
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    4 days ago

    After my teenage years it’s been very rare for me to dig into a band deeply enough to learn anything about their members, so the easiest examples are all going to be women doing clean vocals, which is the one time you can (usually) explicitly tell the difference just by listening. Some of my favorite examples are Liv Kristine’s work in Theatre of Tragedy, Tarja-era Nightwish, the first Stolen Babies album, and Sirenia’s first two albums along with all of Tristania’s discography pre-Rubicon.

    I have two examples that immediately come to mind outside clean vocals:

    Samantha Escarbe is the guitarist for Virgin Black and my understanding is she essentially splits the songwriting load with Rowan London. The Requiem stuff I still need to give more listens, but I think the first two albums are absolutely spectacular music. In “Museum of Iscariot” she does one of my favorite guitar solos I’ve ever heard.

    Angela Gossow’s vocals on Arch Enemy’s “Wages of Sin” album are some of the absolute best in metal. I live for that shit. I never really got into anything else Arch Enemy did though.



  • I found an explanation here. They’re deliberately not including it in the main f-droid repository for security reasons.

    I think it’s extremely unlikely that there’s a reason other than what they’ve stated here, but at the same time this isn’t so important to me that I’m willing to begin making exceptions to my policy against installing any software that doesn’t make it into official f-droid.



  • I use strawberry now, which is a clementine derivative. Having my library in one column on the side and just pulling stuff from the library to a variable custom playlist is my preferred player style. Exaile is also like this, and deadbeef too if your library is organized and you add the filebrowser plugin. I use strawberry over those two because it’s the only one I can get from the main arch repositories and I try to minimize AUR usage.

    Pragha actually fits this style too and is still in the arch repos, but I don’t understand why because it stopped getting upstream updates years ago and is a buggy mess compared to strawberry with no advantages.

    I definitely miss the clementine remote though, being able to control the player from an android phone was so convenient and I don’t know any other player that has similar.





  • If you want to show there are infinitely many primes, one way is to first note that every integer greater than 1 has a prime factor. This is because if an integer n is prime, n is a prime factor of itself, and if n is not prime then it must have a smaller factor m other than 1, 1< m < n. If m is also not prime, it too must have a smaller factor other than 1, and you can keep playing this game but there are only so many integers between 1 and n so eventually you’ll get to a factor of n that has no smaller factors of its own other than 1, which means it is prime.

    Let’s now suppose there is only a finite number of primes, we’ll try to show that this assumption leads to nonsense so can’t be possible.

    We can multiply any finite number of integers together to get a new integer. Let’s multiply all of the primes together to get a new number M. Then M + 1 gives a remainder of 1 when you divide by any prime number. Since dividing by a factor will always give a remainder of 0, none of the prime numbers can be a factor of M + 1. So M + 1 is an integer bigger than 1 with no prime factors. This is impossible, so there must be a mistake somewhere in this argument.

    The only thing we said that we’re not 100% sure is true was that there are a finite number of primes, so that has to be our mistake. So there must be infinitely many prime numbers.