• applebusch (she/her)@lemmy.blahaj.zone
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    2 days ago

    the existence of a sexuality cross product implies the existence of negative gender, which implies the existence of negative gayness. a [1 0 0] * [-1 0 0] relationship would be gayness -1, while being straightness 0, suggesting some kind of anti-gay or opposite gay. rather than attempting to erase the existence of negative gender with an absolute on the cross product we must explore its implications. perhaps a negative gender individual can be found. gender theory must know!

    • vinsombra@lemmy.world
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      2 days ago

      Negative gay is where you are in the closet and trying to overcompensate by being very vocally homophobic, but then in your dark, secret moments, scroll grindr. That can be directly observed at Republican conventions.

    • gandalf_der_12te@lemmy.blahaj.zoneOP
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      2 days ago

      [1, 0, 0] and [-1, 0, 0] must never meet unless they annihilate each other in a violent particle-antiparticle explosion!

      but functionally, they are indistinguishable, since the effective gender is actually the complex gender absolute value squared! yes that’s right, [i, 0, 0] exists as well.